Wimbledon Championships is on the 120th place in local ranking of events in Chinese Wikipediaand on the 83rd place in global ranking of events in all the time.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There are 52 language versions for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
The table below shows the language versions of the article with the highest quality.
The following table shows the most popular language versions of the article.
The following table shows the language versions of the article with the highest popularity in the last month.
The following table shows the language versions of the article with the highest Authors’ Interest.
The following table shows the language versions of the article with the highest Authors’ Interest in the last month.
The following table shows the language versions of the article with the highest number of citations.
Wikipedia readers most often find their way to information on Wimbledon Championships from Wikipedia articles aboutGrand Slam of tennis,Novak Djokovic,Carlos Alcaraz,French Openand Jannik Sinner. Whereas reading the article about Wimbledon Championships people most often go to Wikipedia articles onList of Wimbledon gentlemens singles champions,2024 Wimbledon Championships,List of Wimbledon ladies singles champions,Carlos Alcarazand Roger Federer.
List of Wikipedia articles in different languages (starting with the most popular):
On 8 November 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Zohran Mamdani, James D. Watson, Jacob Elordi, Pluribus, James A. Garfield, Frankenstein; or, The Modern Prometheus, Ed Gein, Frankenstein, Predator: Badlands, Mia Goth.
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(48.29+8.91+100+91.67+18.89)-2.68$$
where:
$$GlobalAI=|⋃↙{lang=1}↖52 Authors_{lang}|=58$$$$PopGlobal=∑↙{lang=1}↖52 PopLocal_{lang}=668697$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas